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def lcs_of_three(X, Y, Z, m, n, o):
L = [[[0 for i in range(o+1)] for j in range(n+1)]
for k in range(m+1)]
for i in range(m+1):
for j in range(n+1):
for k in range(o+1):
if (i == 0 or j == 0 or k == 0):
L[i][j][k] = 0
elif (X[i-1] == Y[j-1] and
X[i-1] == Z[k-1]):
L[i][j][k] = L[i-1][j-1][k-1] + 1
else:
L[i][j][k] = max(max(L[i-1][j][k],
L[i][j-1][k]),
L[i][j][k-1])
return L[m][n][o]
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