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def count_no_of_ways(n, k):
dp = [0] * (n + 1)
total = k
mod = 1000000007
dp[1] = k
dp[2] = k * k
for i in range(3,n+1):
dp[i] = ((k - 1) * (dp[i - 1] + dp[i - 2])) % mod
return dp[n]
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