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def even_or_odd(N):
l = len(N)
if (N[l-1] =='0'or N[l-1] =='2'or
N[l-1] =='4'or N[l-1] =='6'or
N[l-1] =='8'or N[l-1] =='A'or
N[l-1] =='C'or N[l-1] =='E'):
return ("Even")
else:
return ("Odd")
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